99q^2-74q-40=0

Solution for 99q^2-74q-40=0 equation:

99q^2-74q-40=0

a = 99; b = -74; c = -40;
Δ = b2-4ac
Δ = -742-4·99·(-40)
Δ = 21316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21316}=146$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-74)-146}{2*99}=\frac{-72}{198}
=-4/11
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-74)+146}{2*99}=\frac{220}{198}
=1+1/9
$